public class ArithmeticAssignment {
public static void main(String[] args) {
Tester test = new Tester();
test.printTester();
}
}
class Tester{
Tester(){
}
void printTester(){
int i1 = 79 + 3 * (4 + 82 -68) - 7 +19;
int i2 = (179 +21 +10) / 7 + 181;
int i3 = 10389 * 56 * 11 + 2246;
System.out.println(i1);
System.out.println(i2);
System.out.println(i3);
}
}
I think this is what you wanted. I hope this helps!
Answer:
The easiest method to clear a DNS cache is to use either the command line, PowerShell or Windows Server's DNS Manager
Explanation:
You can use either the ipconfig /flushdns (command line), Clear-DnsClientCache (PowerShell) or DNS->(name)->Clear Cache (from the DNS Manager)
source:
https://activedirectorypro.com/clear-windows-dns-cache/
https://www.technipages.com/flush-and-reset-the-dns-resolver-cache-using-ipconfig
Answer:
=F5*$F$12+F5
Explanation:
If we want to increment the salaries in the cell F5, we must multiply the cell F5 by cell F12, and then we must sum that result.
If we want to drag the formula from the cell F5 to F10, we must use the dollar symbol $ to apply the same percent in our formula.
For example:
F12 = 5% = 0.05
F5 = 10,000
=F5*$F$12+F5
=10,000×0.05+10,000 = 10,500
Answer:
B) Measurable.sum (branchAccounts)
Explanation:
The user interface which can be built by adding components to a panel. The sum method that will be used to find total balance of all accounts at branch is measurable.sum, this will layout the sum of specified branch account total. The measurable interface implements public class bank account as measurable sum.
Answer:
Maximum Aggregate I/O Transfer Rate = 1630kb/s
Explanation:
Given
Transfer rate of
Disk Drive = 800Kb/s
DVD Drive = 700Kb/s
Printer = 10Kb/s
VDT = 2Kb/s
Units
DVD = 2
Hard Disk = 2
Printers = 2
VDT Channels = 5
Only one device at a time can be serviced on a selector channel
Both cannot be active at a time
So, the device with higher transfer rate will be granted access (Disk Drive, 800Kb/s)
Maximum aggregate I/O transfer rate in this system is calculated by:
Summation of transfer rate of each device
= 800 * 2 + 2 * 10 + 5 * 2
= 1600 + 20 + 10
= 1630kb/s
