Write a procedure ConvertToBinary that takes an input as a number from 0 to 16 (including 0 but not 16) and converts it to a bin
1 answer:
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Answer:
The program to this question can be described as follows:
Program:
#include <iostream> //defining header file
using namespace std;
int main() //defining main method
{
int x; //defining integer variable
for(x=0;x<=100;x++) //defining loop to count value from 0 to 100
{
if(x%7==0) //check value is divisable by 7
{
cout<<x<<endl; //print value
}
}
return 0;
}
Output:
please find the attachment.
Explanation:
In the above code, an integer variable x is declared, which is used in the for loop, in this loop variable "x" starts from 0 and ends when the value of x is less than and equal to 100.
- Inside the loop an, if block is used that defines a condition that is (i%7==0), it will check, that the value is divided by 7.
- In this loop, a print method is used, that prints its values.
