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SVETLANKA909090 [29]
1 year ago
11

Ramon is going to walk, jog, and run a total distance of 30 miles for charity. He plans to walk 1/2 of the total distance,of the

total distance,jog 1/2 and run the remaining distance. What is the distance Ramon plans to run?
Mathematics
1 answer:
arsen [322]1 year ago
3 0

Ramon is going to walk, jog, and run a total distance of 30 miles for charity.

Total distance travel = 30 miles

He plans to walk 1/2 of the total distance,

1/2 of total distance = 1/2 of 30

1/2 of total distance = 15 miles

The remaining distance = 30 - 15

Remaining distance = 15 miles

He decided to jog 1/2 of remaining distance

1/2 of 15 miles = 7.5 miles

Now, the remaining distance is 30 - 15 - 7.5 = 7.5 miles

Distance travell by running = 7.5 miles

So, Ramon plans to co

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5

Step-by-step explanation:

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3 years ago
Help I need to know how to solve for x
lara [203]

Answer:

the answer would be x=3

Step-by-step explanation:

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4 years ago
Make up this problem yourself 3 divided by 1/2
Helen [10]

Answer:

3 : (1/2) =\frac{6}{1} =6

Step-by-step explanation:

Divide: 3 : \frac{1}{2} =\frac{3}{1} *\frac{2}{1} =\frac{3 * 2}{1*1} =\frac{6}{1} =6

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of \frac{1}{2} is \frac{2}{1}) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.

In words - three divided by one half = six.

8 0
3 years ago
A square pyramid has a height of 6 units and a volume of 70 units? If a square prism has the same base area and volume as the sq
Slav-nsk [51]

Answer:

2 units

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Vpyramid = ⅓ x base area x height

70 = ⅓ x base area x 6

70 = 2 x base area

base area = 70/2 = 35 units

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5 0
3 years ago
Read 2 more answers
Trigonometry help!! - double angle formulae
ivolga24 [154]

Answer:

The two rules we need to use are:

Sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

And we also know that:

sin^2(a) + cos^2(a) = 1

To solve the relations, we start with the left side and try to construct the right side.

a) Sin(3*A) = sin (2*A + A) = sin(2*A)*cos(A) + sin(A)*cos(2*A)

sin(A + A)*cos(A) + sin(A)*cos(A + A)

(sin(A)*cos(A) + sin(A)*cos(A))*cos(A) + sin(A)*(cos(A)*cos(A) - sin(A)*sin(A))

sin(A)*cos^2(A) + sin(A)*cos^2(A) + sin(A)*cos^2(A) - sin^3(A)

3*sin(A)*cos^2(A) - sin(A)*sin^2(A)

sin(A)*(3*cos^2(A) - sin^2(A))

Now we can add and subtract 4*sin^3(A)

sin(A)*(3*cos^2(A) - sin^2(A)) + 4*sin^3(A) -  4*sin^3(A)

sin(A)*(3*cos^2(A) + 3*sin^2(A)) - 4*sin^3(A)

sin(A)*3*(cos^2(A) + sin^2(A)) - 4*sin^3(A)

3*sin(A) - 4*sin^3(A)

b) Here we do the same as before:

cos(3*A) = 4*cos^3(A) - 3*cos(A)

We start with:

Cos(2*A + A) =  cos(2*A)*cos(A) - sin(2*A)*sin(A)

= cos(A + A)*cos(A) - sin(A + A)*sin(A)

= (cos(A)*cos(A) - sin(A)*sin(A))*cos(A) - ( sin(A)*cos(A) + sin(A)*cos(A))*sin(A)

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= cos^3(A) - 3*sin^2(A)*cos(A)

=  cos(A)*(cos^2(A) - 3*sin^2(A))

now we subtract and add 4*cos^3(A)

= cos(A)*(cos^2(A) - 3*sin^2(A)) + 4*cos^3(A) - 4*cos^3(A)

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= -3*cos(A) + 4*cos^3(A)

8 0
3 years ago
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