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Sveta_85 [38]
3 years ago
9

A line perpendicular to the line y=5x+6

Mathematics
1 answer:
Ratling [72]3 years ago
3 0

Answer:

y= -10x +12

Step-by-step explanation:

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Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66
Dmitry_Shevchenko [17]
The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence  , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.
7 0
3 years ago
Read 2 more answers
How do you find the quadratic equation for the roots 3 and 17?
Naily [24]
The roots are 3 and 17 so the distributed equation is

(x-3)(x-17)

distribute 

x²-3x-17x+51

x²-20x+51

I hope I've helped! 
6 0
3 years ago
6(1—a) =3(a—b)+1 4(b—2) =3a Consider the system of equations above. If (a, b) is the solution to the system, then what is the
Jet001 [13]
6-6a=3a-3b+1,    9a-3b=5
<span>4b - 8 =3a,           3a-4b=-8
</span> 
9a-3b=5
(3a-4b=-8 )*(-3 )

 
9a    -3b=    5
-9a+12b=+24
adding both equations
9b=29, b=29/9

3a=4b-8=4*29/9 -8=(4*29-8*9)/9 = 44/9
a=44/27
a-b=44/27 - 29/9=44/27 - 29*3/27=-43/27
this is a correct answer, unfortunately they do not have this choice, probably they made mistake somewhere. I even check the solution of equations by substitution values of a and b into equations

5 0
3 years ago
PLZ HELP WILL GIVE BRAINLISET IF RIGHT!!!
Irina-Kira [14]

Answer:

72.5mph

Step-by-step explanation:

There is an easy way to work this. Divide the miles he drove by 2 so that you know how much he drove in 1/5 hours.

29/2= 14.5miles driven in 1/5 hours

Now, just multiply that number by 5 so that you know how many miles he drove in 5/5 hours (one full hour).

14.5*5= 72.5miles

5 0
3 years ago
Simplify 3(2m^3n^-2)^4
Effectus [21]

Answer:

(48 m^12)/n^8

Step-by-step explanation:

Simplify the following:

3 ((2 m^3)/(n^2))^4

Multiply each exponent in (2 m^3)/(n^2) by 4:

3×2^4 m^(4×3) n^(-2×4)

4 (-2) = -8:

3×2^4 m^(4×3) n^(-8)

4×3 = 12:

(3×2^4 m^12)/(n^8)

2^4 = (2^2)^2:

(3 (2^2)^2 m^12)/(n^8)

2^2 = 4:

(3×4^2 m^12)/(n^8)

4^2 = 16:

(3×16 m^12)/(n^8)

3×16 = 48:

Answer: (48 m^12)/n^8

5 0
3 years ago
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