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GrogVix [38]
1 year ago
14

The steps to solving the expression the quantity of the sum of three squared plus four divided by the absolute value of negative

0.25 end quantity minus 10.4 ÷ 4 are listed below.
Part A: Explain what the missing expression should be in Step 3. (6 points)

Part B: Explain what the missing expression should be in Step 6. (6 points)


Step 1 the quantity of the sum of three squared plus four divided by the absolute value of negative 0.25 end quantity minus 10.4 ÷ 4
Step 2 the quantity of the sum of three squared plus four divided by 0.25 end quantity minus 10.4 ÷ 4
Step 3
Step 4 the quotient of quantity 13 divided by 0.25 end quantity minus 10.4 ÷ 4
Step 5 52 − 10.4 ÷ 4
Step 6
Step 7 49.4
Mathematics
1 answer:
bearhunter [10]1 year ago
7 0

Answer:

Step 3 should be ((9+4)/(0.25))-10.4 divided 4

Step 6 should be 52 - 2.6

I got it right on my exam :)

You might be interested in
A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.
Kobotan [32]

Answer:

The numbers are

-2+3\sqrt{5}   and 3\sqrt{5}

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

so

x=y-2

y=x+2 ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

so

4y+x^2=49 ----> equation B

substitute equation A in equation B

4(x+2)+x^2=49

solve for x

x^2+4x-41=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+4x-41=0

so

a=1\\b=4\\c=-41

substitute in the formula

x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}

x=\frac{-4\pm\sqrt{180}} {2}

x=\frac{-4\pm6\sqrt{5}} {2}

x=-2\pm3\sqrt{5}

so

The positive real number is

x=-2+3\sqrt{5}

Find the value of y

y=x+2

y=-2+3\sqrt{5}+2

y=3\sqrt{5}

6 0
4 years ago
I need some help please! ^_^
Degger [83]
Perpendicular lines will have negative reciprocal slopes. What that means is if u have a slope of 1/2, to find the negative reciprocal, flip the slope and change the sign.......flip 2/1, change the sign -2/1 or just -2. So the negative reciprocal for the slope of 1/2 is -2. 

A. y = 1/5x + 3.....slope here is 1/5, so for a perpendicular line, u r gonna need an equation with the slope of -5.....and that would be : y + 3 = -5(x + 2).

B. Parallel lines will have the same slope. y = 5x - 2...the slope here is 5...so a parallel line will have a slope of 5.

y = mx + b
slope(m) = 5
(8,-2)...x = 8 and y = -2
now we sub, we r looking for b, the y intercept
-2 = 5(8) + b
-2 = 40 + b
-2 - 40 = b
-42 = b

so ur parallel equation is : y = 5x -42
7 0
3 years ago
Solve for the variable k.<br> m<br> __ = x<br> k
Tresset [83]
M/k=x
(m)m/k=x(m)
k=xm

Because you are diving one the side where m/k, you need to multiply m to both sides to get rid of it on one. Therefore, you are left with K=XM
5 0
3 years ago
Jonna ran a mile in a physical education class
olganol [36]
Okay what’s the question ?
5 0
3 years ago
Read 2 more answers
Can someone help me and show your work thanks
GREYUIT [131]

Answer:

D) $8.20

Step-by-step explanation:

82 x 0.1 = 8.2

4 0
3 years ago
Read 2 more answers
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