I draw the two triangles, see the picture attached.
As you can see, angle 1 and 2 are vertically opposite angles because they are formed by the same two crossing lines and they face each other.
Angles <span>ABQ and QPR, as well as angles BAQ and QRP, are alternate interior angles because they are formed by </span><span>two parallel lines crossed by a transversal, and they are inside the two lines on opposite sides of the transversal.</span>
Hence, Allison's correct claims are:
1 = 2 because they are vertically opposite angles. BAQ = QRP because they are alternate interior angles. Therefore Allison, in order to prove her claim, can use the AA similarity theorem: if two angles of a triangle are congruent to two angles of the other triangle, then the two triangles are similar.
Answer:
2x + 12
Step-by-step explanation:
Example of Associative Property Addition:
a + (b+c) = b + (a+c)
Now, implement it to the given expression:
(2x+8) + 4 = 2x + (8+4)
That simplifies to:
2x + 12
Answer:
(5,2)
Step-by-step explanation:
i am unsure of what your question is but if you want the point of intersection of the two lines its (5,2)
Answer is -23
Add 4 from both sides
Subtract 5 from both sides
Then divide 7
These are alternate exterior angles
they alternate (or cross) the traversal (the center line)
and they are exterior (they are both outside)
and they are equal
100 = x + 105 subtract 105 from both sides
-105 -105
-5 = x
x = -5