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3 years ago

-1/2 +2=-x+7 how do you figure this out

Mathematics

1 answer:

Feliz [49]3 years ago

3 0

Answer:

x = 5.5

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

$-\frac{1}{2} +2=-x+7$

$-\frac{1}{2} +2= 1.5$

$1.5=-x+7$

-7 -7

$-5.5 = -x$

Divide both sides by -1.

$5.5 = x$

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The process of finding which prime numbers you need to multiply together to get a certain number. ex: 21=7x3 20=2x2x5

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Saiah Copeland sells tennis equipment. He is guaranteed a minimum monthly salary of $1,500 per month plus 5.75% of his total sal

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Answer:

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Step-by-step explanation:

Given data

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3 years ago

5(-3x - 2) - (x - 3) = -4 (4x +5) + 13

S_A_V [24]

Start off by distributing the numbers into the parentheses:

5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
-15x - 10 - (x - 3) = -16x - 20 + 13

(Note: It's super important to be careful when opening up negative parentheses! -(x-3) is not just - x - 3, it is actually -x + 3 since the negative is distributed in every number!)

-15x - 10 - x + 3 = -16x - 20 + 13
-16x - 7 = -16x - 7
-16x = -16x
0 = 0

There is an infinite number of solutions in this equation.

(When you get 0=0 when solving for a variable, that means that said variable will have infinite solutions, that is, any number plugged into the equation will work)

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Hi please help me thanksss<br>pls provide workings too thanks :)

anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

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We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

2π

or x=

6n±2

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

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-1/2 +2=-x+7 how do you figure this out​

-1/2 +2=-x+7 how do you figure this out