Given,
slope(m)=-3/4
y intercept (c)=-5
Then,
equation in slope intercept form is
y=mx+c
or, y=(-3/4)×x+(-5)
or, y=-3/4×x-5
Answer: 33
Step-by-step explanation:
(f of g)(2) = f(g(2))
g(2) = -2(2) = -4
f(-4) = (-4)^2 - 3(-4) + 5 =
16 - - 12 + 5 =
16 + 17 =
33
It’s 2 because it starts at 6 and the next time the line meets a point is at (4,-1) you go down one and over two and you put x/y so it’s 2/1 which is 2. I think that’s right
Answer:
y - 3x = -10
Step-by-step explanation:
Complete question
<em>Choose the equation below that represents the line passing through the point (2, -4) with a slope of 3</em>
The standard equation of a line in point-slope form is y-y0 = m(x-x0)
Given
x0 = 2
y0 = -4
alope m = 3
Substitute
y - (-4) = 3(x - 2)
y + 4 = 3(x - 2)
y + 4 = 3x - 6
y - 3x = -6 - 4
y - 3x = -10
Hence the required equation is y - 3x = -10
