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kifflom [539]
1 year ago
10

If f(x)=8-5x, find each value 1. f(4c) 2. f(2-k) 3. f(4p+3) Please and thanks!

Mathematics
1 answer:
Studentka2010 [4]1 year ago
7 0

Problem 1

We replace every copy of x with 4c and simplify like so:

f(x) = 8 - 5x

f(4c) = 8 - 5*4c

f(4c) = 8 - 20c is the answer

This is equivalent to -20c+8.

====================================================

Problem 2

Same idea as before, but this time we'll plug in x = 2-k

Each x gets replaced with (2-k)

f(x) = 8 - 5x

f(2-k) = 8 - 5(2-k)

f(2-k) = 8 - 10 + 5k

f(2-k) = -2 + 5k

This is the same as saying 5k - 2.

====================================================

Problem 3

The steps are similar to earlier.

f(x) = 8 - 5x

f(4p+3) = 8 - 5(4p+3)

f(4p+3) = 8 - 20p - 15

f(4p+3) = -7-20p

This is the same as writing -20p - 7.

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Answer:

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What is the vertex of the function x^2-6x+8=0 ?
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Distance formula: \sqrt{ (x_{2} -  x_{1})^{2} + ( y_{2} -  y_{1})^{2} }

Plug in your values for x_{2},  x_{1},  y_{2},  y_{1} using (-8, -7) and (8, -4) and solve.

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