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3 years ago

Determine the Prime factorization of each number. 36 b. 120 c. 258 d. 63

Mathematics

2 answers:

Snezhnost [94]3 years ago

5 0

Answer:

the answer to this question is 36

Paha777 [63]3 years ago

5 0

Answer:

Step-by-step explanation:

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X/3=-19<br> What is the value of x

Molodets [167]

<h3>I'll teach you how solve X/3=-19</h3>

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X/3=-19

Multiply both sides by 3:

3x/3= 3(-19)

Simplify:

x= -57

Your Answer Is x= -57

plz mark me as brainliest :)

8 0

3 years ago

Read 2 more answers

A plane averaged 500 mph on a trip going east, but only 200 mph on the return trip. The total flying time in both directions was

adoni [48]

Let's assume time taken by plane on one way distance as 't'

The total flying time in both directions was 10.5 hr

so, time taken in other direction =10.5-t

now, we are given

A plane averaged 500 mph on a trip going east

so, total distance of one way is

$=500t$

total distance of other way is

$=200(10.5-t)$

now, we can that distance is same from both sides

so, we get

$500t=200(10.5-t)$

now, we can solve for t

$500t=2100-200t$

$700t=2100$

$t=3$

now, we can find one way distance

$=500\times 3$

$=1500$ miles..............Answer

6 0

3 years ago

4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$