Answer:
h[g{f(x)}] = -(8x² + 40x + 50) is the answer.
Step-by-step explanation:
The given functions are f(x) = 2x + 5 , g(x) = x² and h(x) = -2x.
We have to find the value of h[g{f(x)}]
To get the value we will find the value of g{f(x)} first.
g{f(x)} = (2x + 5)²= 4x²+ 25 + 20x
Then we will find the value of h[g{f(x)}]
h[g{f(x)}] = -2(4x²+ 20x + 25) = (-8x² - 40x -50)
So the answer is h[g{f(x)}] = -(8x² + 40x + 50)
Since base angles of an isosceles triangle are congruent the other base angle is also 65. since the three angles together sum to 180 thst leaves 180-65-65=180-130 = 50 degrees for the vertex angle
Answer:
-4x^5+20x^4-40x^3+40x^2-20x+4
Step-by-step explanation:
The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
Answer:
12
Step-by-step explanation:
easy peasy
