Answer:
58240
Step-by-step explanation:
1425 ------ 45600
1820 ------ x
1425*x = 1425x
45600*1820 = 82992000
1425x = 82992000
82992000/1425 = x
58240 = x
Answer:
D) 2x² + 4x - 30
Step-by-step explanation:
Follow the FOIL method:
FOIL =
First
Outside
Inside
Last
...and is the order you multiply to solve:
(x + 5)(2x - 6) =
(x)(2x) = 2x²
(x)(-6) = -6x
(5)(2x) = 10x
(5)(-6) = -30
Combine like terms. Simplify:
2x² -6x + 10x - 30 = 2x² (-6x + 10x) - 30 = 2x² + 4x - 30
2x² + 4x - 30 is your answer.
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Answer:
The Least Common Multiple ( LCM ) is also referred to as the Lowest Common Multiple (LCM) and Least Common Divisor (LCD). For two integers a and b, denoted LCM (a,b), the LCM is the smallest positive integer that is evenly divisible by both a and b. For example, LCM (2,3) = 6 and LCM (6,10) = 30.
Step-by-step explanation:
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.