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Rufina [12.5K]
1 year ago
7

Find the 13th term of the arithmetic sequence whose common difference is d=7 and whose first term is a1=-3

Mathematics
1 answer:
timama [110]1 year ago
3 0

Answer:

81

Step-by-step explanation:

the formula for an arithmetic sequence:

aₙ = a₁ + (n-1)d

where aₙ = the nth term

a₁ = the 1st term = -3

n = the term number = 13

d = the common difference = 7

Plugging in those values into the formula to find a₁₃:

a₁₃ = -3 + (13-1)7

= -3 + (12)7

= -3 + 84

= 81

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<u>Using Section Formula.</u>

<u />If \ the \ line \ segment \ AB \ where  \ A = (x _1, y_1) \ and \ B = (x_2, y_2) \ divided \ by \ P =(x , y) \ in \ the \ ratio \ a : b,\\\\Then \  the \ points \  of \  P  \ \\\\x = \frac{ax_2 + bx_1}{a+b} \ and \ y = \frac{ay_2 + by_1}{a+b}<u />

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<u />

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