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Rufina [12.5K]
1 year ago
7

Find the 13th term of the arithmetic sequence whose common difference is d=7 and whose first term is a1=-3

Mathematics
1 answer:
timama [110]1 year ago
3 0

Answer:

81

Step-by-step explanation:

the formula for an arithmetic sequence:

aₙ = a₁ + (n-1)d

where aₙ = the nth term

a₁ = the 1st term = -3

n = the term number = 13

d = the common difference = 7

Plugging in those values into the formula to find a₁₃:

a₁₃ = -3 + (13-1)7

= -3 + (12)7

= -3 + 84

= 81

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</span>2b + 3 > 11 reduces to 2b > 8, which in turn reduces to b > 4:  (4, infinity).

It may be helpful to graph these sets.

If you really do mean   "<span>10 < –2b or 2b + 3 > 11," then the "solution" is made up of two sub-intervals:  b < -5 and b > 4.

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3 years ago
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OlgaM077 [116]

Answer:

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3 years ago
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Answer: 259/260 or 0.99615 (depending on which answer format your teacher wants)

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There is only one way Matthew can get the correct answer, and there are 260 - 1 = 259 ways to get the wrong answer. We divide 259 over 260 to get the probability of getting the incorrect answer, which is 259/260.

If you need this fraction in decimal form, then use a calculator to find that 259/260 = 0.99615 approximately

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What do you mean about that
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just open the parentheses

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