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3 years ago

How do you solve r-119=70

1 answer:

6 0

R-199=70
remember you can do anything to an equaton as long as you do it to both sides

r-119=70
add 119 to both sides
r+119-119=119+70
r+0=189
r=189

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100 POINTS!! A company has 400 employees. There are 300 female employees. There are 80 employees who are under the age of 25. Th

Fittoniya [83]

Answer:

probability of randomly selecting an employee who is female and under the age of 25= 0.15

In percentage= 15%

Step-by-step explanation:

There are 300 female employees. There are 80 employees who are under the age of 25

Probabilty of choosing a female employees= 300/400

Probabilty of choosing a female employees= 0.75

Probabilty of choosing an employees under the age of 25

= 80/400

Probabilty of choosing an employees under the age of 25

= 0.2

probability of randomly selecting an employee who is female and under the age of 25= 0.2*0.75

probability of randomly selecting an employee who is female and under the age of 25= 0.15

In percentage= 0.15*100

In percentage= 15%

4 0

3 years ago

Given the measures a = 10, b = 40, and A = 30°, how many triangles can possibly be formed?

arlik [135]

Answer:

no triangle can be formed with the given values (i.e 0 triangle).

Step-by-step explanation:

Given;

length of side a, = 10

length of side b, = 40

angle A, = 30°

Apply sine rule to determine the angle of the second side (B);

$\frac{sin \ A}{a} = \frac{sin \ B}{b} \\\\\frac{sin \ 30^0}{10} = \frac{sin \ B}{40}\\\\sin \ B = 40(\frac{0.5}{10} )\\\\sin \ B = 2$

The maximum sine function is 1, there is no sine function that will be equal to 2, so there is no triangle that can be formed with the given values.

8 0

2 years ago

Question 2 of 5

AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is $f(n)=f(n-1)+d, f(1)=a,n\geq 2$ and the explicit formula is $f(n)=a+(n-1)d$ , where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is $f(n)=rf(n-1), f(1)=a,n\geq 2$ and the explicit formula is $f(n)=ar^{n-1}$ , where a is the first term and r is the common ratio.

The first recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+5$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(5)$

$f(n)=5+5(n-1)$

Therefore, the correct option is A, i.e., $f(n)=5+5(n-1)$ .

The second recursive formula is:

$f(1)=5$

$f(n)=3f(n-1)$ for $n\geq 2$ .

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

$f(n)=5(3)^{n-1}$

Therefore, the correct option is F, i.e., $f(n)=5(3)^{n-1}$ .

The third recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+3$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(3)$