Answer:
The option is C i.e 115°, 65°. proof is given below.
Step-by-step explanation:
Given:
ABCD is a quadrilateral.
m∠ A = 100 + 5x
m∠ B = 77 - 4y
m∠ C = 106 + 3x
m∠ D = 47 + 6y
To Prove:
ABCD is a parallelogram if opposing angles are congruent by finding the measures of angles.
m∠ A = m∠ C and
m∠ B = m∠ D
Proof:
ABCD is a quadrilateral and is a parallelogram if opposing angles are congruent.
∴ m∠ A = m∠ C
On substituting the given values we get
∴ 100 + 5x = 106 +3x
∴
m∠ A = 100 + 5x = 100 + 5 × 3 =100 + 15 = 115°
m∠ C = 106 + 3x = 106 + 3 ×3 =106 + 9 = 115°
∴ m∠ A = m∠ C = 115°
Similarly,
∴ m∠ B = m∠ D
77 - 4y = 47 + 6y
10y = 77 - 47
10y =30
∴
m∠ B = 77 - 4y =77 - 4 × 3 = 77 - 12 = 65°
m∠ D = 47 + 6y = 47 + 6 × 3 = 47 + 18 = 65°
∴ m∠ B = m∠ D = 65°
Therefore the option is C i.e 115°, 65°
I believe its 21 sorry if im wrong
Answer:
ΔRHS ≅ ΔNKW
Step-by-step explanation:
We are given that, in the triangles RHS and NKW.
∠H = ∠K
Side HS = KW.
∠S = ∠W
Now, using the ASA congruence criteria, which states that when two corresponding angles of the triangles are equal with the included side between them is equal, then both the triangles are congruent.
Hence, according to ASA criteria, ΔRHS ≅ ΔNKW.
Answer:
252:36
Step-by-step explanation:
7:1
B:G
36:x
1 = 36
7=252
Answer:20h + 21 is the only one equivalent to 4(5h + 4) + 5
Step-by-step explanation: