Answer:
Options c and d
Step-by-step explanation:
Given is a graph with period pi.
ii) The graph is discontinuous
iii) x intercepts are say (a) units to the right of y axis and repeats for every interval of pi.
Fix the function
a) y = sinx cannot be this graph because sinx is a continuous graph
b) y =cosx cannot be this graph because cosx is a continuous graph
e) y = sec x is undefined for the range (-1,1) since the given graph is defined in this interval, secx is not answer.
f)y = csc x is undefined for the range (-1,1) since the given graph is defined in this interval, cscx is not answer.
c) y=tanx is a discontinuous graph at x = odd multiples of pi/2
Hence the given graph can be of the form y =- tan (2x+a) which shows reflection over y axis,
d) y = cotx can also be this graph with adjustments for period and horizontal shift.
So answers are c and d
Answer:
The answer is B because the numbers in the geometric sequence are being multiplied by 2.
I think it is -160 I’m not sure tho
Simplify both sides of the equation
3x+1/10 = x+ -1/7
Subtract x from both sides
3x+1/10 -x = x+ -1/7 -x
2x+1/10 = -1/7
Subtract 1/10 from both sides
2x+1/10 - 1/10 = -1/7 -1/10
2x= -17/70
Divide both sides by 2
2x/2 = -17/70/2
x= -17/140
decimal x will equal -0.121
Ask any questions you want and I hope that's help !
Siince 2nd equation is already equal a, subsitute b-2 for a in the other equation
b-2-3b=28
-2-2b=28
add 2 to both sides
-2b=30
divide both sides by -2
b=-15
sub back
a=b-2
a=-15-2
a=-17
(a,b)
(-17,-15)
3rd choice
