Answer:
The ball is in the air for approximately 3.27 seconds ⇒ answer A
Step-by-step explanation:
* Lets explain how to solve the problem
- The height of the ball is modeled by the function
h(t) = -4.9 t² + 16 t
- We need to find the time that the ball is in the air
- The ball is in the air from its initial position and then return to the
same position
- That means h(t) = 0 because h(t) represent the height of the ball
from its initial position
∵ h(t) = -4.9 t² + 16 t
∵ h(t) = 0
∴ 0 = -4.9 t² + 16 t
- Add 4.9 t² to both sides
∴ 4.9 t² = 16 t
- Subtract 16 t from both sides
∴ 4.9 t² - 16 t = 0
- Take t as a common factor
∴ t (4.9 t - 16) = 0
- Equate each factor by 0
∴ t = 0 and 4.9 t - 16 = 0
∵ 4.9 t - 16 = 0 ⇒ add 16 for both sides
∴ 4.9 t = 16
- Divide both sides by 4.9
∴ t = 3.2653
∴ t = 0 ⇒ initial position
∴ t = 3.2653 seconds ⇒ final position
* <em>The ball is in the air for approximately 3.27 seconds</em>
Answer: 1/4
1. Convert 1/1 into fourths
1/1 = 4/4
2. Evaluate
5/4 - 4/4 = 1/4
Answer:
73
Step-by-step explanation:
72 - 35 = 107
180 - 107 = 73
107 + 73 = 180
Answer:
144
Step-by-step explanation:
Answer:
There is a 25.14% probability that the order will not be met during a month.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean \mu and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
.
The order will not be met if
. So we find the pvalue of Z when
, and subtract 1 by this value.



has a pvalue of 0.7486.
So there is a 1 - 0.7486 = 0.2514 = 25.14% probability that the order will not be met during a month.