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Gala2k [10]
2 years ago
13

What is limit of startfraction x cubed minus 1 over x minus 1 endfraction as x approaches 1?

Mathematics
1 answer:
iogann1982 [59]2 years ago
3 0

The value of the given limit lim ₓ → 1 (x³ - 1)/(x - 1) = <u>3</u>.

In the question, we are asked what is the limit of startfraction x cubed minus 1 over x minus 1 endfraction as x approaches 1, that is, lim ₓ → 1 (x³ - 1)/(x - 1).

Unique real numbers are limits in mathematics. Let us consider a real-valued function "f" and a real number "c", the limit is normally defined as lim ₓ → c f(x) = L. The phrase is to be understood as "the limit of f of x, as x approaches c equals L." The right arrow indicates that function f(x) approaches the limit L as x approaches c. The "lim" displays the limit.

The value of the given limit can be calculated as follows:

lim ₓ → 1 (x³ - 1)/(x - 1)

= lim ₓ → 1 (x³ - 1³)/(x - 1), Since 1³ = 1

= lim ₓ → 1 (x - 1)(x² + x + 1)/(x - 1) , using the formula: a³ - b³ = (a - b)(a² + ab + b²)

= lim ₓ → 1 (x² + x + 1), Cancelling (x - 1) in the numerator and the denominator, since x → 1, that is, x is approaching 1 and not equal to 1, implying that x - 1 ≠ 0.

= (1² + 1 + 1), Substituting x = 1, and removing the limit.

= 3.

Thus, the value of the given limit lim ₓ → 1 (x³ - 1)/(x - 1) = <u>3</u>.

Learn more about limits at

brainly.com/question/10434858

#SPJ4

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Determine whether each expression is equivalent to 49^2t – 0.5.
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Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
4 years ago
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