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Gala2k [10]
1 year ago
13

What is limit of startfraction x cubed minus 1 over x minus 1 endfraction as x approaches 1?

Mathematics
1 answer:
iogann1982 [59]1 year ago
3 0

The value of the given limit lim ₓ → 1 (x³ - 1)/(x - 1) = <u>3</u>.

In the question, we are asked what is the limit of startfraction x cubed minus 1 over x minus 1 endfraction as x approaches 1, that is, lim ₓ → 1 (x³ - 1)/(x - 1).

Unique real numbers are limits in mathematics. Let us consider a real-valued function "f" and a real number "c", the limit is normally defined as lim ₓ → c f(x) = L. The phrase is to be understood as "the limit of f of x, as x approaches c equals L." The right arrow indicates that function f(x) approaches the limit L as x approaches c. The "lim" displays the limit.

The value of the given limit can be calculated as follows:

lim ₓ → 1 (x³ - 1)/(x - 1)

= lim ₓ → 1 (x³ - 1³)/(x - 1), Since 1³ = 1

= lim ₓ → 1 (x - 1)(x² + x + 1)/(x - 1) , using the formula: a³ - b³ = (a - b)(a² + ab + b²)

= lim ₓ → 1 (x² + x + 1), Cancelling (x - 1) in the numerator and the denominator, since x → 1, that is, x is approaching 1 and not equal to 1, implying that x - 1 ≠ 0.

= (1² + 1 + 1), Substituting x = 1, and removing the limit.

= 3.

Thus, the value of the given limit lim ₓ → 1 (x³ - 1)/(x - 1) = <u>3</u>.

Learn more about limits at

brainly.com/question/10434858

#SPJ4

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25 points!! please answer
melomori [17]

ac is the answer

hope that helps

6 0
3 years ago
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Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
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2/3 times 1/2 =<br> IN SIMPLEST FORM <br> I GIIVE BRAINY
Zinaida [17]

Answer:

1/3!

Step-by-step explanation:

Look us Cymath on g0ogle, its a calculator that shows its work!

8 0
2 years ago
50 PTS ANSWER ALL &lt;3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
3 years ago
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What is the answer to this
blsea [12.9K]
Using the calculator it is 27.47 round off to 27.5
6 0
3 years ago
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