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Snezhnost [94]
2 years ago
13

Simplify the problem 6(x-2)+7

Mathematics
2 answers:
Alika [10]2 years ago
5 0

Answer:

step 1: open bracket

6x - 12 + 7

= 6x -5

Maurinko [17]2 years ago
4 0

Answer:

6x - 5

Step-by-step explanation:

distribute

6x - 12 + 7

combine like terms

6x - 5  

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Write the quadratic function in vertex form.<br><br> y = x2 - 2x + 5
Jlenok [28]
Vertex form formula: y = a(x-h)^2 +k, with vertex (h,k)
There are multiple ways to find the vertex. One way is to find the roots and then find the x value exactly in between them, because this parabola is symmetrical. 

0 = (x - 3)(x + 2), so x = 3 and -2. The point directly in the middle is x = 1/2 = h 

To find the y value of the vertex, plug in 1/2 to the equation.

(1/2)^2 - 2(1/2) + 5 = 4.25 = k

y = (x - 0.5)^2 + 4.25
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3 years ago
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7 &gt; z + 18 ≥ 6 please help me!
sp2606 [1]

7 > z + 18 ≥ 6

Subtract 18 from all 3 parts:

7-18 > z +18 -18 ≥ 6-18

-11 > z ≥ -12

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3 years ago
You put $939 into an investment at 8% for 6 years. What will the balance be at the end of 6 years?
WINSTONCH [101]

Answer:

At simple interest it will be 939+939×6×0.08=$1389.72.

Step-by-step explanation:

4 0
3 years ago
How to solve Y=-1/3x+7
Vikki [24]

Answer:

x+3y=21 in standard form

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3 years ago
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Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0
3 years ago
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