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AleksAgata [21]
1 year ago
11

The access code for a card security system consist of four digits the first digit cannot be 4 and the last digit must be odd. Ho

w many different codes are avalible
SAT
1 answer:
Deffense [45]1 year ago
5 0

Different codes for access code which are available are: 4000

_ _ _ _

1 2 3 4

1st blank can be filled with the following possibilities, here the conditions are:

1)The first digit cannot be 4

2)The first digit cannot be 0 also since it makes the access code 3 digits hence

From 1 to 9 except 4 there are  8 possible ways to fill that blank

<u>8</u>

2nd blank can be filled with any number between 0 to 9 in 10 possible ways

<u>8</u> <u>10 </u>

3rd blank can be filled with any number between 0 to 9 in 10 possible ways

<u>8</u> <u>10</u> <u>10</u>

4th blank can be filled with any odd numbers between 0 to 10 - 1,3,5,7,9

<u>8</u> <u>10</u> <u>10</u> <u>5</u> = 8 x 10 x 10 x 5 = 4000

Hence to conclude that 4000 available codes are there for the access security card

To know more about permutations and combinations please follow this link

brainly.com/question/1216161

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The vertices of the square are given as:

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<h3>How to determine the congruent perpendicular bisectors.</h3>

Start by calculating the slope of diagonal ce using:

m = \frac{y_2 -y_1}{x_2  -x_1}

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m = \frac{-1-1}{3  -1}

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Hence, -1 = -\frac {1}{1} shows that the diagonals are congruent perpendicular bisectors.

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