Answer:
I believe that this is what you mean. (y^3+3y+7)*(8y^2+y+1)
Step-by-step explanation:
So your answer would be: 8y^5+y^4+25y^3+59y^2+10y+7
Have a nice day!
I really hope this helps!
Answer:
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
Step-by-step explanation:
The null and alternative hypotheses are stated as
H0: u ≥ 1750 i.e the mean is less and equal to 1750
against the claim
Ha: u > 1750 ( one tailed test) the mean is greater than 1750
Sample mean = x`= 1754
Population mean = u = 1750
Population deviation= σ = 65 pounds
Sample size= n = 100
Applying the Z test
z= x`- u / σ/ √n
z= 1754- 1750 / 65/ √100
z= 4/6.5
z= 0.6154
The significance level alpha = 0.1
The z - value at 0.1 for one tailed test is ± 1.28
The critical value is z > z∝.
so
0.6154 is < 1.28
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
AB =
The midpoint os segment AB =
The midpoint is:
(1,-4)
The mean is 23 because it is the middle number
