Let's assume we were given 2 numbers: 15 and 30. Their sum is:

We want to express it as the product of GCF and another sum.
15 is divisible by: 1, 3, 5, 15
30 is divisible by: 1, 2, 3, 5, 6, 10, 15, 30
The greatest number that appears in 2 series is 15.


In this case sum of two numbers can always be written as:
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
0-t-14
Step-by-step explanation:
Its the first one I don't want to type
Answer:
90 calories in a banana.
Step-by-step explanation:
O = B - 20 where O is the number calories in an orange and B is a that in banana.
Also 7B = 9O
From the above O = 7B / 9 so substituting in the first equation:
7B / 9 = B - 20
7B = 9B - 180
2B = 180
B = 90.
Answer:
B. 48
Step-by-step explanation:
Multiply all the numbers of choices together.
trim levels: 3
colors: 4
interior: 4
number of combinations = 3 * 4 * 4 = 48