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MariettaO [177]
3 years ago
15

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0

Answer: (A) vertical asymptote: x = 2, horizontal asymptote: y = 1

<u>Step-by-step explanation:</u>

f(x) = \dfrac{1}{x-2}+1

<u>Vertical Asymptote</u> is the restriction on the x-value.  The denominator cannot be zero, so x - 2 ≠ 0  ⇒  x ≠ 2

The restricted value on x is when x = 2  <em>which is the vertical asymptote</em>

<u>Horizontal Asymptote</u> (H.A.) is the restriction on the y-value.  This is a comparison of the numerator (n) and denominator (m).  There are 3 rules that will help you:

  • n > m    No H.A. (use long division to find slant asymptote)
  • n = m    H.A. is the coefficient of n divided by coefficient of m
  • n < m    H.A. is 0

In the given problem, n < m so y = 0, however there is also a vertical shift of up 1 so the H.A. also shifts up.  This results in H.A. of y = 1


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strojnjashka [21]

Answer:

P(X = 3) = 0.14680064

Step-by-step explanation:

Formula=============================

p\left( X=k\right)  =C^{k}_{n}p^{k}(1-p)^{n-k}\ \ ;\ k\in \left\{ 0,\ldots ,n\right\}

……………………………………………………………………..

Given :

n = 8

p = 0.2

1 - p = 1 - 0.2 = 0.8

k = 3

Then

p\left( X=3\right)  =C^{3}_{8}(0.2)^{3}(0.8)^{5}

               =0.14680064

4 0
1 year ago
How do I solve this
Montano1993 [528]
Use arccos...cos^-1 so

cos^-1 (0.8195)

it equals 34.96522689°
6 0
3 years ago
PLEASE HELP!!!
just olya [345]

Answer:

-3(1.5n - 1)

your welcome

3 0
3 years ago
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stiks02 [169]
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3 years ago
Complete the tables of values.
Vladimir [108]

Answer:

a=1\\b=\frac{1}{16}\\\\c=\frac{1}{256}\\\\d=1\\e=\frac{4}{9}\\\\f=\frac{16}{81}

Step-by-step explanation:

For the orange table:

<em> </em>Substitute the corresponding values of <em>x</em> into the function f(x)=4^{-x}, then:

For a:

x=0

f(0)=4^0=1

For b:

x=2

f(x)=4^{-2}=\frac{1}{16}

For c:

x=4

f(x)=4^{-4}=\frac{1}{256}

For the blue table:

<em> </em>Substitute the corresponding values of <em>x</em> into the function g(x)=(\frac{2}{3})^x, then:

For d:

x=0

g(x)=(\frac{2}{3})^0=1

For e:

x=2

g(x)=(\frac{2}{3})^2=\frac{4}{9}

For f:

x=4

g(x)=(\frac{2}{3})^4=\frac{16}{81}

3 0
3 years ago
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