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3 years ago

Simplify the ratio 24/56

2 answers:

8 0

How to solve:
Step 1 : Note down the given ratio from the questions.

Step 2 : Find the greatest common factor, and divide the numerator and denominator by that value.
Answer: 3:7

kakasveta [241]3 years ago

6 0

The Answer Would Be 3/7
Hope This Helps :)

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PLEASE PLEASE PLEASEEEEE HELP!!!

IRINA_888 [86]

Step-by-step explanation:

Volume of cylinder

= πr²h

= π×3²×6

= 54π

= 169.56units³

5 0

3 years ago

Read 2 more answers

A map of a highway has a scale of 2 inches =39 miles. The length of the highway on the map is 6 inches. There are 11 rest stops

wolverine [178]

Find the distance of the rest stop in the original map

Divide by 6 because there are 7 rest stop
Find the real distance of the rest stop using proportion

step 2
Find the distance of the rest stop in the new map
using proportion

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3 years ago

Which must be true of a quadratic function whose vertex is the same as the y-intercept ?

jeka94

A quadratic function whose vertex is the same as the y-intercept has the equation
y=x^2+k (where k is the y-intercept, with vertex (0,k))

Since the vertex coincides with the y-intercept, the axis of symmetry is x=0.

3 0

3 years ago

The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin

anzhelika [568]

Answer:

$Length=17.5\ in\\\\Width=11.5\ in$

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

$A=201.25\ in^2\\\\P=58\ in$

The steps are:

1. Solve for the "l" from the formula $A=lw$ :

$A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}$

2. Substitute $l=\frac{201.25}{w}$ into the formula $P=2l+2w$ and solve for "w":

$58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0$

Applying the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$ , we get:

$x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5$

3. Substitute $w_1=17.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{17.5}=11.5$

4. Substitute $w_2=11.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{11.5}=17.5$

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

$l=17.5\ in\\\\w=11.5\ in$