Please see attached photo for question

Mathematics

1 answer:

ra1l [238]1 year ago

5 0

For the function g(x), the graph is shown and the domain of that function is set of all integer numbers.

Domain of a function is all possible input values for that function.

Here, the domain of g(x) is set of all integers numbers

The x intercept of g(x)

The x intercept is when the value of y is zero, analysing the graph the x intercept can be interpreted as -5 and 1

The y intercept is when the value of x is zero, analysing the graph the y intercept can be interpreted as 1

From the graph,

g(4) is 1

Therefore, For the function g(x), the graph is shown and the domain of that function is set of all integer numbers.

To learn more about function refer here

brainly.com/question/24335034

#SPJ9

You might be interested in

Find sin 2a and cot 2a:

geniusboy [140]

Answer:

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}$

Step-by-step explanation:

$\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\$

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}$