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Artyom0805 [142]
1 year ago
9

Please see attached photo for question

Mathematics
1 answer:
ra1l [238]1 year ago
5 0

For the function g(x), the graph is shown and the domain of that function is set of all integer numbers.

Domain of a function is all possible input values for that function.

Here, the domain of g(x) is  set of all integers numbers

The x intercept of g(x)

The x intercept is when the value of y is zero, analysing the graph the x intercept can be interpreted as -5 and 1

The y intercept is when the value of x is zero, analysing the graph the y intercept can be interpreted as  1

From the graph,

g(4) is 1

Therefore, For the function g(x), the graph is shown and the domain of that function is set of all integer numbers.

To learn more about function refer here

brainly.com/question/24335034

#SPJ9

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50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

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Answer:

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Answer:

Step-by-step explanation:

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From the given right angle triangle,

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To determine EF, we would apply

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EF = 8Cos49 = 8 × 0.6561

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