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Bumek [7]
4 years ago
10

true /falseCompression of entries in the term-document matrix can be used to reduce run-time storage and execution-time requirem

ents.
Computers and Technology
1 answer:
Anvisha [2.4K]4 years ago
3 0

Answer: True

Explanation: Document-term matrix is the matrix used in the group of documents for defining the elements frequency in mathematical terms.It is also referred as term-document matrix.

The compression in the element entries helps in the reduction of the size which creates more storage space. It also decreases the time for processing the data by changing the huge data block into smaller units.Thus, the statement given is true.

 

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How do you turn on the Track Changes feature in a spreadsheet?
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2. Suppose a computer using direct mapped cache has 220 words of main memory and a cache of 32 blocks, where each cache block co
Advocard [28]

Answer:

(a) The block size = 16 words (b) the format for the sizes of the tag, block, and word fields are stated below:

Tag Block Offset  

11 bits 5 bits 4 bits

(c)The memory address 0DB63 will map to 22nd block and 3 byte of a block. (d)  The main advantage of the cache is, when the cache block is made larger or bigger then, there are fewer misses. this occur when the data in the block is used.

One of the disadvantage is that if the data is not used before the cache block is removed from the cache, then it is no longer useful. here there is also a larger miss penalty.

Explanation:

Solution

(a)The Cache of 32 blocks and the memory is word addressable  

The main memory size is not stated, so let's consider it as 2^20  

The main memory size = 2^20  

The block size = 16 words  

The Number of blocks = main memory size/ block size = 2^20/16. = 2^16= 64 K words.

(b) The Main memory is 2^20, which says it is 1 M words size and it requires 20 bits  

Now,

From which 32 cache block requires 2^5, 5 bits and block size means offset requires 2^4, 4 bits

Thus, the sizes of the tag, block, and word fields are stated below:

Tag Block Offset  

11 bits 5 bits 4 bits

(c)The hexadecimal address is 0DB63 , its binary equivalent is  

0000 1101 1011 0110 0011  

The tag = ( first 11 bits) = 0000 1101 101  

block = ( next 5 bits ) = 1 0110  

offset = ( next 4 bits ) = 0011  

Therefore, the memory address 0DB63 will map to 22nd block and 3 byte of a block.

(d) The main advantage of the cache is that, when the cache block is made larger or bigger then, there are fewer misses. this occur when the data in the block is used.

One of the disadvantage is that if the data is not used before the cache block is removed from the cache, then it is no longer useful. here there is also a larger miss penalty.

3 0
3 years ago
Problem 8 - Recursive Divisible by 3 and 5 Complete the divBy3And5 function which accepts a list of integers. The function shoul
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The recursive function divBy3And5 is defined in Python and is found in the attached image.

In the base case, the function divBy3And5 tests if the input list is empty. If so, the tuple returned is (0, 0). This means no numbers are divisible by three and no numbers are divisible by five.

The recursive step gets the first element of the list and

  • If divisible by 3, it sets <em>count_of_3</em> to 1, else it leaves it as 0
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It then makes a recursive call on the remaining elements, and stores it in a variable as follows

   <em>divBy3And5_for_remaining_elem</em> = divBy3And5(remaining_elements)

Then, it returns the tuple

       (<em>divBy3And5_for_remaining_elem</em>[0] + <em>count_of_3</em>,

                <em>divBy3And5_for_remaining_elem</em>[1] + <em>count_of_5)</em>

Learn more about recursion in Python: brainly.com/question/19295093

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