All categories

3 years ago

Where does the oracle11g server store information about objects in the database, including information about constraints?

1 answer:

4 0

The oracle11g server stores information about objects in the database, including information about constraints in the tables. An Oracle database is a set of files that store Oracle data in persistent disk storage.A database instance is a set of memory structures that manage database files.

You might be interested in

Mesh networks:__________.

postnew [5]

Answer:

b. typically contain more circuits in the network than in star or ring networks

Explanation:

In mesh architecture, all computers are connected to each other. In mesh all nodes connect directly and non hierarchical to each other so as to efficiently route data.

Mesh combines the benefits of both ring and star networks. It usually provide relatively short routes through the network (compared to ring networks) and provide many possible routes through the network to prevent one circuit from becoming overloaded (as compared to star network). Mesh network uses decentralized routing with each network performing its own routing.

Mesh network typically contain more circuits in the network than in star or ring networks and are more expensive than ring networks

7 0

3 years ago

Which type of photoreceptor is best able to process bright light and color?

Scilla [17]

Cone cells, or cones, are one of three types of photoreceptor cells in the retina of mammalian eyes. They are responsible for color vision and function best in relatively bright light, as opposed to rod cells, which work better in dim light.

4 0

3 years ago

Ms. Lawson, a primary school teacher, told her students that a photograph of the president is in the public domain. What does sh

dezoksy [38]

Answer:

He belongs to the nation

7 0

2 years ago

Many say that computers are changing learning as radically as did printing in its age. how are computer technologies changing le

Iteru [2.4K]

Computers are broadening horizons of learning and cutting back on limitations. practically all the knowledge of the worls is only a few clicks away

7 0

3 years ago

Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th

ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0

3 years ago