All you have to do is just put the same variable on the same side as each other.
Answer:
0, 1, 2
Step-by-step explanation:
The solution to a system of equations given graphically is at the intersection of the individual graphs.
Graph (1)
There is no intersection between the 2 graphs so no solution
Graph (2)
There is one point of intersection between the 2 graphs so 1 solution
Graph (3)
There are two points of intersection between the 2 graphs so 2 solutions
Answer:
Step-by-step explanation:
Isolate any variable, x or y, but since y has already been isolated, use y to solve for x.
Substitute y into the first equation -3x-3y=3
This equals -3x - 3 (-5x - 17) = 3
Distribute to get -3x + 15x + 51 = 3
Then bring like terms together. -3x + 15x = 3 - 51
12x = -48
Solve for x
x = -4
Substitute -4 for x in the equation: y = -5x - 17
y = − 5x − 17
y = (−5) (−4) − 17
y = 20 - 17
y = 3 ( Simplify both sides of the equation)
Answer:
x = − 4 and y = 3
You have to combine like terms (terms that have the same variable(x,y....) and power/exponent)²³
(4x³ - 4 + 7x) - (2x³ - x - 8) Distribute -1 into (2x³ - x - 8)
(4x³ - 4 + 7x) + (-)2x³ - (-)x - (-)8 (two negative signs cancel each other out and become positive)
(4x³ - 4 + 7x) - 2x³ + x + 8 Now combine like terms
4x³ - 2x³ + 7x + x - 4 + 8 (I rearranged for the like terms to be next to each other)
2x³ + 8x + 4 It is equivalent to B
Combine like terms
(I rearranged for the like terms to be next to each other)
It is equivalent to D
(x² - 2x)(2x + 3) Distribute x² into (2x + 3) and distribute -2x into (2x + 3)
(x²)2x + (x²)3 + (-2x)2x + (-2x)3
When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together
2x³ + 3x² - 4x² - 6x Combine like terms
2x³ - x² - 6x It is equivalent to A
[Info]
When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (You can combine the exponents only if they have the same variable)
For example:
(You can't combine them because they have different exponents of y and x)