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1 year ago

What can you prove congruent from your given

Mathematics

1 answer:

Molodets [167]1 year ago

4 0

Answer:

a. line OL bisects angle MLN

b. triangle MLO is congruent to triangle OLN

c. line OL proves that they are congruent through reflexive property.

Step-by-step explanation:

hope this helps!

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Problem number 26 of the Rhind Papyrus says:

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Answer:

X=12 on edg

Step-by-step explanation:

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3 years ago

The product of 0.6 and a number is 31.8 more than the number . Find the number

Kobotan [32]

0.6n = n + 31.8
0.6n - n = 31.8
-0.4n = 31.8
n = 31.8 / -0.4
n = -79.5

6 0

3 years ago

Justin ran 5.5 miles in 49.5 minutes. On average, how many minutes did it

olchik [2.2K]

49.5/ 5.5
= 9 minutes to run one mile

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3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

4 years ago

Write 0.78 repeating as a fraction is simplest form,

valina [46]

You would write 39 over 50.

5 0

4 years ago

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