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MA_775_DIABLO [31]

3 years ago

5

Select the correct answer. What is the simplified form of this expression? 3x + (8x − 16) A. 11x − 16 B. -5x − 16 C. 11x + 16 D.

-5x

2 answers:

AysviL [449]3 years ago

4 0

Answer:

a.11x-16

Step-by-step explanation:

3x+(8x-16)you multiply the signs in the bracket

that is 3x+8x-16

=11x-16

fgiga [73]3 years ago

4 0

Answer: 11x-16

Step-by-step explanation:

We multiplied to find our answer.

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Choose the polynomial that is written in standard form 7x^5+8x^8+27x

Nataliya [291]

Answer: Option d: -3*x^4*y + 2*x^2*y^2 + 5*y^3

Step-by-step explanation:

In standard form, the first term of the polynomial must be the term with the highest degree and on each subsequent term the degree decreases. In the case of two variables, the degree is equal to the sum of the exponents.

Then the correct option is d.

Where the degree of the first term is (4 + 1) = 5

The degree of the second term is (2 + 2) = 4

The degree of the third therm is 3.

We can see that the degree decreases as the term number increases, then the polynomial written in standard form is:

-3*x^4*y + 2*x^2*y^2 + 5*y^3

8 0

3 years ago

K-10/2=7 two Step Equation

aivan3 [116]

I hope this helps you

K-10=7.2

K-10=14

K=14+10

K=24

6 0

3 years ago

Someone help me out please

uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

$(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\ (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4$ .

2 step (A): simplify to obtain the final radical term on one side of the equation.

$-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2$ .

3 step (F): raise both sides of the equation to the power of 2 again.

$(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2$ .

4 step (E): simplify to get a quadratic equation.

$4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0$ .

5 step (D): use the quadratic formula to find the values of x.

$D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}$ .

6 step (C): apply the zero product rule.

$x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}$ .

Additional 7 step: check these solutions, substituting into the initial equation.

3 0

3 years ago

The value of 8y 2 –5y +1 when y= 1 is …………

ELEN [110]

Answer:

4

Step-by-step explanation:

8(1)^2 -5(1) +1

8(1) -5(1) +1

8 -5 +1

4

4 0

2 years ago

What value of c makes the equation -3c/4=24 true ?

Sonbull [250]

Creo que C es igual a -6

4 0

3 years ago

Read 2 more answers