1)Y=165000(1-0.04)^t
2)y=165000(1-0.04)^20=?? Use the calculator
Answer:
98$
Step-by-step explanation:
Suppose x-6 is listed as a possible answer. That is zero if x = 6. So put x=6 into the original x^2 + 4x - 60 to get 6^2 + 4*6 - 60 = 36 + 24 -60 = 0. hence x-6 is a factor.
Answer (x-6)
on this hand :x-5 is not a factor, because plugging x=5 into does not work.
Answer:
The correct option is;

Step-by-step explanation:
The given expression is presented as follows;

Which can be expanded into the following form;

From which we have;


Therefore, substituting the value of n = 50 we have;


Which gives;



Therefore, we have;
.