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2 years ago

6

a store had a sale to celebrate veterans day. Every item in the store is advertised as 1/5 off the original price. If an item is

marked with a sale price of $140m what was its original price?

1 answer:

makkiz [27]2 years ago

3 0

Answer:

$175

Step-by-step explanation:

let the original price be x

if 1/5 is off the price then the sells is at 4/5

4/5 of x = 140

thus,

4/5* x=140

4x = 140*5

x=700/4

x=$175

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A city police officer using radar checked the speed of 26 cars as they were travelling down a city street and the data is given

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Answer: The distribution of the data set is positively skewed.

<u>Explanation: </u>

In order to see whether the given data set is symmetric, positively skewed or negatively skewed, we will find the mean, median and mode of the given data set.

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For positively skewed distribution, $Mean > Median>Mode$

For negatively skewed distribution, $Mean < Median$

The mean of the given data set is given below:

$Mean = \frac{27+23+22+38+43+24+25+23+22+54+31+30+29+48+27+25+29+28+26+33+25+21+23+34+20+23}{26}$

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Now, the Median is:

To find the median we need to sort the data in ascending order as:

$20,21,22,22,23,23,23,23,24,25,25,25,26,27,27,28,29,29,30,31,33,34,38,43,48,54$

$Median=\left(\frac{N+1}{2} \right)^{th} item$

$=\left(\frac{26+1}{2}\right)^{th} item$

$=13.5^{th} item$

$=26+0.5 \times (27-26)$

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Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

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$M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}$

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k" (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

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We subtract 7 to all values smaller than the median.

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The new mean will be:

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Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

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