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1 year ago

A dilation with a scale factor of 3. 5 and centered at the origin is applied to PQ¯¯¯¯¯ with endpoints P(2, 5) and Q(2, 1)

Mathematics

1 answer:

velikii [3]1 year ago

7 0

Answer: The answer is P'(7, 17.5) and Q'(7, 3.5).

Step-by-step explanation: Given that a line segment PQ is dilated with a scale factor of 3.5 where origin is the centre of dilation.

The end points of segment PQ are P(2, 5) and Q(2, 1).

Therefore, after dilation, the coordinates of the end points become

Thus, the coordinates of P' are (7, 17.5) and the co-ordinates of Q' are (7, 3.5).

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Which is the solution to the equation 8.25 + 1/4 W = 10.75? Round to the nearest hundredth if necessary.

murzikaleks [220]

$8.25+\dfrac{1}{4}w=10.75\ \ \ \ |-8.25\\\\\dfrac{1}{4}w=2.5\ \ \ |\cdot4\\\\w=10$

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3 years ago

PLEASE HELP: The mass of a ball is 128 g. It has a density of 0.5 g/cm³. What is the volume of the ball? Show your work and plac

tiny-mole [99]

Answer:

Part 1) The volume of the ball is 256 cm³

Part 2) The radius of the ball is 3.94 cm

Step-by-step explanation:

Part 1) we know that

The density is equal to divide the mass by the volume

D=m/V

Solve for the volume

The volume is equal to divide the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

Part 2) what is the radius of the ball?

we know that

The volume of the sphere (ball) is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$V=256\ cm^{3}$

assume

$\pi =3.14$

substitute and solve for r

$256=\frac{4}{3}(3.14)r^{3}$

$768=(12.56)r^{3}$

$r^{3}=768/(12.56)$

$r=3.94\ cm$

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2 years ago

Math question I need help with

muminat

Let's you and me discuss a few things that you already know:

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The y-intercept is on the y-axis, so 'x' is zero there.

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You say that x=0 and look at what 'y' is.

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3 years ago

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Elanso [62]

Answer:

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3/4÷ 3/8 =

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2 years ago

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Eduardwww [97]

Answer:

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6 0

2 years ago