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OLga [1]
1 year ago
6

Given fx = vneiolfjwijfewjfwe

Mathematics
1 answer:
Sindrei [870]1 year ago
5 0

<u>Part</u><u> </u><u>(</u><u>a</u><u>)</u>

f(3)=5(3)-3=\boxed{12}

<u>Part</u><u> </u><u>(</u><u>b</u><u>)</u>

5x-3=-28 \\ \\ 5x=-25 \\ \\ x=\boxed{-5}

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Answer:

<h2>5</h2>

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

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collect the like terms

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Comparing the resulting expression with ax²+bx

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Also;

12x = bx

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The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a is equivalent to 5

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