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natita [175]
3 years ago
11

Use the algebra tiles tool to model the equation 5x + (–6) = 6x + 4. What is needed to model the equation? Check all that apply.

5 negative x-tiles on the left 6 positive x-tiles on the right 4positive unit tiles on the right 6 negative x-tiles on the right 6 negative unit tiles on the left
Mathematics
2 answers:
aleksandrvk [35]3 years ago
5 0

Answer:

b,c, and E  /   6 positive x-tiles on the right , 4 positive unit tiles on the right, 6 negative unit tiles on the left

Step-by-step explanation:

just took the quiz

Maslowich3 years ago
4 0

Answer:

b,c,and e

Step-by-step explanation:

i just took the assignment

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Arthur paid $0.84 for 0.25 pound of potato salad. How much does one pound cost?
SashulF [63]
$3.36 answer
Step-by-step explanation:
1 pound is 4 times 0.25 pounds.
$0.84 = 0.25 pounds
1 pound = $0.84 times 4
1 pound = $3.36
5 0
2 years ago
Read 2 more answers
A mobile phone dealer sold a total of 74 mobile phones in july and 8 less than that in august. In september the sale is even 5le
EastWind [94]

Answer:

201 mobile phones

Step-by-step explanation:

July: 74 mobile phones

August: 74 - 8 = 66 mobile phones

September: 66 - 5 = 61 mobile phones

74 + 66 + 61 = 201 mobile phones

Hope this helps!

4 0
2 years ago
Read 2 more answers
Compare the value of √(100/25) to the value of √100/√25.
olga2289 [7]

Answer:

4 16 2.000

5 25 2.236

6 36 2.449

7 49 2.646

Step-by-step explanation:

7 0
3 years ago
If x&gt;7, then |x|&gt;7. |y|&gt;7, so y=7<br><br><br> Valid or invalid?
Alex

\text{if }x>7\text{, then }|x|>7 is a valid argument

|y|>7\text{, so }y=7 is not a valid argument

For the first argument: \text{if }x>7\text{, then }|x|>7

From the definition of absolute value function

|x|=x   if x\ge0

That is every positive number is its own absolute value. Since

x>7\implies x\ge0,

we can argue that

x>7\implies |x|>7

so the first argument is valid

For the second argument: |y|>7\text{, so }y=7

From the definition of absolute value function

|y|:=\left \{ {y\text{  if }y\ge0}\atop{-y\text{  if }y

This means that

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{-y>7\text{  if }y

or

|y|>7:=\left \{ {y>7\text{  if }y\ge0}\atop{y

no part of the definition allow for the option y=7. So the second argument is not valid.

Learn more here: brainly.com/question/11897796

7 0
3 years ago
The table below shows some inputs and outputs of the invertible function f etc ​
Snowcat [4.5K]

Answer:

(a)\ f^{-1}(-15) = -6

(b)\ f^{-1}(4) + f(9)=0

Step-by-step explanation:

Given

The attached table

(a)\ f^{-1}(-15)

This represents an inverse function.

So, we look into x row for its value.

i.e.

f^{-1}(-15) = -6

(b)\ f^{-1}(4) + f(9)

Just like (a)

f^{-1}(4) = -11 ---- by looking into the x rows

f(9) = 11

So:

f^{-1}(4) + f(9)=-11 + 11

f^{-1}(4) + f(9)=0

4 0
3 years ago
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