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Tems11 [23]
3 years ago
13

carlos has 1,294 cups of frosting if each cake he frost uses 2 cups of frosting how many cakes can he frost

Mathematics
1 answer:
docker41 [41]3 years ago
5 0
1294/2 = 647 cakes that he can frost
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Robert had $300 in the bank yesterday. Then, Robert bought a sofa for $500, but didn't realize that he overdrew from his bank. H
strojnjashka [21]

Answer:-200

Step-by-step explanation:

300-500=-200

3 0
3 years ago
The weight of a child in 1990 was 40 lb. By 2005, the child's weight
Maslowich

Answer:

225%

Step-by-step explanation:

1. Divide the new weight by the original weight.

90/40 = 2.25.

2. Multiply by 100 to get the percentage.

2.25 x 100 = 225%

5 0
3 years ago
PPPLLLZZZ HELP I'LL GIVE BRAINLIEST
kati45 [8]

Allen's work is not written properly so I have rearranged it as shown below:


Original problem) –8.3 + 9.2 – 4.4 + 3.7.

Step 1) −8.3 + 9.2 + 4.4 + 3.7 Additive inverse

Step 2) −8.3 + 4.4 + 9.2 + 3.7 Commutative property

Step 3) −8.3 + (4.4 + 9.2 + 3.7) Associative property

Step 4) −8.3 + 17.3


We can see that in step 1), Allen changed -4.4 into +4.4 using additive inverse. Notice that we are simplifying not eliminating -4.4 as we do in solving some equation. Hence using additive inverse is the wrong step.


Alen should have collect negative numbers together and positive numbers together.

Add the respective numbers then proceed to get the answer.


–8.3 + 9.2 – 4.4 + 3.7

= –8.3 – 4.4 + 9.2 + 3.7

= -12.7 + 12.9

= 0.2



6 0
3 years ago
Read 2 more answers
What is the distance between 5,4 and -1,1
spayn [35]

Answer:

3\sqrt{5}

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)

d = \sqrt{(-1-5)^2+(1-4)^2}

   = \sqrt{(-6)^2+(-3)^2}

   = \sqrt{36+9}

   = \sqrt{45}

   = 3\sqrt{5} ← exact value

   ≈ 6.71 ( to 2 dec. places )

8 0
3 years ago
All you need is on the photo
mariarad [96]

Answer:

4^{-3}

Step-by-step explanation:

We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}

5 0
3 years ago
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