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erica [24]
11 months ago
11

The next step in the translation of this mrna will be the formation of a peptide bond between which two of the numbered amino ac

ids?
Computers and Technology
1 answer:
blondinia [14]11 months ago
4 0

The bond between Amino acid 2 and amino acid 3 two of the numbered amino acids. The correct option is A.

<h3>What is protein translation?</h3>

In genomics, translation is the process by which information encoded in messenger RNA (mRNA) directs the addition of amino acids during protein synthesis.

It is divided into three stages: initiation, elongation, and termination. After being processed, the mRNA transports the instructions to a ribosome in the cytoplasm.

The ribosome, which is made up of rRNA and proteins, is where translation takes place.

The bond formed by amino acids 2 and 3 (two of the numbered amino acids).

Thus, the correct option is A.

For more details regarding protein translation, visit:

brainly.com/question/16305501

#SPJ1

Your question seems incomplete, the missing part of question is attached below:

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What two devices in a computer should be considered "black boxes," and should never be opened due to risks involving charged cap
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The two devices in a computer that should be considered "black boxes," and should never be opened due to risks involving charged capacitors are MONITOR and POWER SUPPLY.

Explanation:

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Assume you are using the text's array-based queue and have just instantiated a queue of capacity 10. You enqueue 5 elements and
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The indices of the internal array elements that hold the remaining elements is c) 2 to 4

<h3>Calculations and Parameters:</h3>

For us to create a capacity of 10 for the queue, we would enqueue:

We would create a queue of capacity 10:

<h3>Queue q(10);</h3>

We add elements/enqueue 5 elements to the queue :

  • q.queueEnqueue(10);
  • q.queueEnqueue(5);
  • q.queueEnqueue(8);
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Printing this would give:

q. queueDisplay()

10, 5, 8, 9, 2

Next, we would remove elements/dequeue 2 elements from the queue :

q. queuedequeue();

q. queuedequeue();

Printing it would be:

q. queueDisplay()

8 ,9, 2

Observing this, the deletion/dequeue starts from the front/first index.

The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4

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