Solution:
Users of an access point share the transmission capacity of the access point. The throughput a user gets is called the bits per seconds.
Thus this is the required answer.
Answer:
Line 8 gives a compiller Error
Explanation:
In line 8, the statement: if (number >= 0 && <= 100) will give a compiller error because when using the logical and (&&) It is required to state the same variable at both sides of the operator. The correct statement would be
if (number >= 0 && number <= 100). The complete corrected code is given below and it will display the output "passed"
#include <iostream>
using namespace std;
int main()
{
int number = 5;
if (number >= 0 && number <= 100)
cout << "passed.\n";
else
cout << "failed.\n";
return 0;
}
I believe it's <span>C. TLD
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