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MaRussiya [10]
1 year ago
6

3/14 divided by 2/7 equal

Mathematics
1 answer:
Aleks [24]1 year ago
3 0

Sandra, this is the solution:

3/14 / 2/7

We use the multiplicative inverse or reciprocal and convert the division in a multiplication, as follows:

7/2 is the reciprocal or multiplicative inverse of 2/7

3/14 * 7/2

And now:

3 * 7 = 21 in the numerator

14 * 2 = 28 in the denominator

21/28 that we can simplify, this way:

21/28 = 3/4

3/14 divided by 2/7 equal to 3/4

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Since 100% = $120,

105% = $126.

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Solve for k.<br> 2k = -7.56
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k= -/+3.78

Step-by-step explanation:

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8 0
4 years ago
A pond 85 feet across; 1 inch = 4 feet
enot [183]
Well... all u have to do is 85 divided by 4 which equals 21.25..... unless there is another part of the question!!
3 0
4 years ago
You spin the spinner once.
MAVERICK [17]

Answer:

50%

Step-by-step explanation:

The P(even or divisor of 28) = P(even) + P(divisor of 28) - P(even and divisor of 28). The P(even) = 2/4 = 1/2. The P(divisor of 28) = 2/4 = 1/2. The P(even and divisor of 28) = 2/4 = 1/2 as 2,4 are even numbers and divisors of 28.

1/2 + 1/2 - 1/2 = 1/2 = 50%

3 0
2 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
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