Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you!
Answer:
a) 0.1535
b) 0.4866
c) 0.8111
Step-by-step explanation:
The probability that the next call come within the next t minutes is:
According to this model,
a) the probability that a call in comes within 1/2 minutes is 
=0.1535
b) the probability that a call in comes within 2 minutes is 
=0.4866
c) the probability that a call in comes within 5 minutes is 
=0.8111
Answer:
142.92
Step-by-step explanation:
Answer:
There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the solution has an intersection with an infinite number of solutions.
Step-by-step explanation:
Its right on edg
