For the given function h(x) = x² +5 ,the domain of the function h(x) maps by the set { -2, -1, 0, 1, 2 } then the range of the function h(x) is given by the set { 5, 6, 9 } .
As given in the question,
Given function is equal to :
h(x) = x² +5
Domain of the function h(x) = x² +5 maps by the set { -2, -1, 0, 1, 2 }
Range of the function h(x) = x² +5 is represented by the set as follow :
Substitute the value x = -2, -1, 0, 1, 2 in the function h(x) = x² +5 we get,
h(-2) = (-2)² + 5
= 9
h(-1) = (-1)² + 5
= 6
h(0) = (0)² + 5
= 5
h(1) = (1)² + 5
= 6
h(2) = (2)² + 5
= 9
Range of the function is represented by the set : { 5, 6, 9 }
Therefore, for the given function h(x) = x² +5 ,the domain of the function h(x) maps by the set { -2, -1, 0, 1, 2 } then the range of the function h(x) is given by the set { 5, 6, 9 }.
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