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Verdich [7]
2 years ago
10

Give an example of how you use positive and negative numbers, and explain the meaning of 0 in your example.

Mathematics
1 answer:
EastWind [94]2 years ago
6 0

Answer:

Meanings of the numbers:

Most numbers represent an amount. Positive numbers represent above zero. Zero is the only number that does not represent an amount. It means nothing. When you go lower than nothing, you are in the negative numbers. Negative numbers represent absent values pretty much.

How I would use them in every day life:

I would use positive numbers to represent... maybe something I'm trying to get at a store. Ex: 4 bananas

I would use negative numbers to... maybe look at the temperature. Ex: -16 degrees Fahrenheit. Negative numbers are in temperature all the time.

Hope this helps! (^-^)

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Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio
Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2}  } }{N} }

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\

3. Caclulate Standard deviation:

SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2}  } }{5} }

SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251

7 0
3 years ago
EASY MATH QUESTION! WILL GIVE BRAINLIEST! (MUST EXPLAIN HOW YOU GOT YOUR ANSWER!) By the end of the first quarter of a football
castortr0y [4]

Answer:

+73 yards.

Step-by-step explanation:

Since we have the first two quarters, we can simply work out the yardage for each game and add them together to get the total.

42-9 = 33 (first game)

58-18 = 40 (second game)

Therefore his total yardage was +73.

6 0
3 years ago
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Which statements are true for the given quadrilaterals? Choose all answers that are correct. A. All trapezoids are quadrilateral
svetlana [45]
Trapezoids always have 4 sides, so this is true. All rhombuses have parallel sides, so B is true also. A trapezoid has two sides that are not parallel, so C is not true. (remember, you only have to find one instance where your statement is false for it to be false) And for D, all rhombuses are kite-shaped so D is not true. A and B are true. Hope this helps. :) 
8 0
3 years ago
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The function f(t) = t2 + 6t − 20 represents a parabola.
Novay_Z [31]
Part A: f(t) = t² + 6t - 20
              u = t² + 6t - 20
         + 20            + 20
      u + 20 = t² + 6t
u + 20 + 9 = t² + 6t + 9
      u + 29 = t² + 3t + 3t + 9
      u + 29 = t(t) + t(3) + 3(t) + 3(3)
      u + 29 = t(t + 3) + 3(t + 3)
      u + 29 = (t + 3)(t + 3)
      u + 29 = (t + 3)²
          - 29       - 29
              u = (t + 3)² - 29

Part B: The vertex is (-3, -29). The graph shows that it is a minimum because it shows that there is a positive sign before the x²-term, making the parabola open up and has a minimum vertex of (-3, -29).
------------------------------------------------------------------------------------------------------------------
Part A: g(t) = 48.8t + 28           h(t) = -16t² + 90t + 50
            | t |   g(t)  |                          |  t  |  h(t)  |
            |-4|-167.2|                          | -4 | -566 |
            |-3|-118.4|                          | -3 | -364 |
            |-2| -69.6 |                          | -2 | -194 |
            |-1| -20.8 |                          | -1 |  -56  |
            |0 |   -28  |                          |  0  |   50  |
            |1 |  76.8 |                          |  1  |  124 |
            |2 | 125.6|                          |  2  | 166  |
            |3 | 174.4|                          |  3  | 176  |
            |4 | 223.2|                          |  4  | 154  |
The two seconds that the solution of g(t) and h(t) is located is between -1 and 4 seconds because it shows that they have two solutions, making it between -1 and 4 seconds.

Part B: The solution from Part A means that you have to find two solutions in order to know where the solutions of the two functions are located at.
4 0
3 years ago
Read 2 more answers
Suppose the odds against winning the lottery as 48,000,000 to 1. What is the probability of the event of winning the lottery giv
kupik [55]

The probability according to the given scenario will be "\frac{1}{48,000,001}".

According to the question:

  • The odds against winning the lottery are 48,000,000 to 1.
  • Favorable outcome = 1

→ The total outcome will be:

= 48,000,000 +1

= 48,000,001

As we know,

→ P(E) = \frac{Favorable \ outcomes}{Total \ outcomes}

By putting the values, we get

→           =\frac{1}{48,000,001}

Thus the above response is right.

Learn more about Probability here:

brainly.com/question/15739211

8 0
2 years ago
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