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2 years ago

12

Find the indicated limit, if it exists. See file below.

1 answer:

White raven [17]2 years ago

6 0

Answer:

c

Step-by-step explanation:

The limit exists because it's continuous since they equal each other

when x approaches zero.

Substitute both expressions with x=0 and both of them will equal 2, so the limit should be 2.

You might be interested in

The measure of the exterior angle of the triangle is what degree?

RSB [31]

Answer:

92°

Step-by-step explanation:

By exterior angle theorem:

$(2x - 2) \degree = x \degree + 45 \degree \\ \\ (2x - 2 - x) \degree = 45 \degree \\ \\ (x - 2) \degree = 45 \degree \\ \\ (x - 2) = 45 \\ \\ x = 45 + 2 \\ \\ x = 47 \\ \\ (2x - 2) \degree = (2 \times 47 - 2)\degree \\ \\ (2x - 2) \degree = (94 - 2)\degree \\ \\ (2x - 2) \degree = 92\degree \\ \\ measure \: of \: the \: exterior \: angle \\ = 92 \degree$

4 0

3 years ago

Use the formula d = rt to find the distance d a long-distance runner can run at a rate r of 9 1/2 miles per hour for time t of 1

boyakko [2]

multiply the 2 numbers

9 1/2 * 1 3/4 =

19/2 * 7/4 = 133/8 = 16 5/8 miles

6 0

3 years ago

A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,

Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

So

$P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017$

Probability of a defective item being produced on the first shift:

1% of 50%. So

$P(A \cap B) = 0.01*0.5 = 0.005$

What is the probability that it was manufactured during the first shift?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941$

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0

3 years ago

A number N divided by -9 is -16

lianna [129]

Answer: no

Step-by-step explanation:

algebraic expression for "a number , n, divided by 4 is 4. I

3 0

3 years ago

A/10*5/3=1 find a PLEASE

alexandr1967 [171]

Answer:

<em>The answer is a = 6.</em>

8 0

3 years ago

Read 2 more answers