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AlexFokin [52]
1 year ago
6

In the xy-plane, the line determined by the points (2,k) and (k, 32) passes through the origin. Which of the following could be

the value of k ? A) 0 B) 4 C) 8 D) 16
Mathematics
1 answer:
alexgriva [62]1 year ago
6 0

1) Considering that those points (2,k) and (k,32) determines one same line, within the plane. Therefore we can say that

2) Considering that since they pass through the origin then their x -coordinate is equal to zero, and their y coordinate as well so

3) We can state that as a matter of fact (2, k) and (K, 32) can be rewritten as (2,0) and (0,32)

k=0

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What is the factored form of x^2 - 4x - 5?
ser-zykov [4K]

we are given

x^2-4x-5

we can use formula

x^2-(a+b)x+ab=(x-a)(x-b)

so, we have

a+b=4

ab=-5

now, we can solve for a and b

and we get

a=5, b=-1

now, we can plug it in formula

x^2-4x-5=(x-5)(x+1) ............Answer

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3 years ago
What is the solution to the liner equation <br><br> -12+3b-1=-5-b
Natalija [7]

Answer:

b=2

Step-by-step explanation:

-12+3b-1=-5-b

Combine like terms

-13 +3b = -5-b

Add b to each side

-13+3b+b = -5-b+b

-13+4b = -5

Add 13 to each side

-13+13 +4b = -5+13

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6 0
3 years ago
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Help with these questions
balandron [24]

9514 1404 393

Answer:

  16) No

  17)  (c)

Step-by-step explanation:

For a lot of multiple-choice matrix problems, a simple test is all that is needed to determine the correct answer.

16) The determinant of A is (-2)(-2) -(2)(-3) = 10. So, we expect to see values in the inverse matrix that are 0.2 and 0.3. Alas, they're not there. The matrices are not inverses.

  A^-1 = [[-.2, .3][-.2, -.2]]

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17) The matrices are both 3×3, so their product is possible (eliminates choice D). The upper left term is different among the answer choices, so we can determine the correct one by computing that term only.

  BA=C

  c11 = (5)(1) +(7)(5) +(3)(-1) = 5 +35 -3 = 37

This matches the third choice (C).

If you use a calculator to compute the full matrix product, it matches choice C in all details.

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3 years ago
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ok bud, better be good content then ill sub

Step-by-step explanation:

3 0
3 years ago
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What is the strongest classification of the figure formed by the following points?
tatiyna

Answer:

A. Parallelogram

Step-by-step explanation:

The given points are;

(-10, -4), (-7, -8), (-5, -4), (-2, -8)

Let 'A' represent the point (-10, -4), let 'B' represent the point (-7, -8), let 'C' represent the point (-5, -4), and let 'D' represent the point (-2, -8), we have;

The (horizontal) distance between points A and C = -5 - (-10) = 5

The (horizontal) distance between points B and D = -2 - (-7) = 5

Therefore;

The length of \overline {AC} = The length of \overline {BD}

The length of \overline {AB} = √((-10 - (-7))² + (-4 - (-8))²)) = 5

The length of \overline {CD} = √((-5 - (-2))² + (-4 - (-8))²)) = 5

∴ The length of \overline {AB} = The length of \overline {CD}

\overline {AC} is parallel to the horizontal axis

\overline {BD} is parallel to the horizontal axis

∴ \overline {AC} ║ \overline {BD}

Given that \overline {AB} = \overline {CD}, then \overline {AB} ║ \overline {CD}

Therefore, the quadrilateral ABCD is a parallelogram

(The angle ∠ABD = 180 - arctan (4/3) ≈ 126.9 > 90, therefore, the parallelogram ABCD is not a rectangle.)

6 0
3 years ago
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