In the isosceles trapezoid ABCD, draw two perpendiculars AM and BL from A and B to the side CD.
Now, LM = BA = 5 m
CD = CL + LM + MD
= CL + 5 + CL (CL = MD)
= 2CL + 5
But, CD = 11
Therefore, 2CL + 5 = 11
2CL = 11 - 5
= 6
CL = 6/2 = 3m
MD = 3m
Now, consider the right triangle AMD.
We have,
= 
= 16 - 9
= 7
Hence, height of the isosceles trapezoid = AM = 
Answer:
a) Response error
b) coverage error
c) coverage error
Step-by-step explanation:
Given situation:
(a) You want to know about the dating habits of college students, so you go to a dorm meeting and ask students how many dates they have had in the last year.
Solution:
In such situations the dating habits is a private matter for every individual and would not be truy expressed or conveyed in a dorm meeting. The true response would either be false or hidden in context of a public gathering.. So the likely error would be " Response error"
Given situation:
b) You want to know how often people attend religious services, so you stand outside a particular church on Sunday and ask entering individuals how often they attend.
Solution:
The collection of sample from a "particular" church limits the diversity of responses. The spread of the data might be skewed to certain geographical or population or ethnical locations. A better coverage would be recommended for accurate sampling. Hence, "coverage error"
Given situation:
(c) You want to know how often people eat at McDonald's, so you stand outside a particular McDonald's and ask entering customers how often they eat at McDonald's.
Solution:
The collection of sample from a "particular" McDonalds limits the diversity of responses. The spread of the data might be skewed to certain geographical or population or ethnical or lifestyles. A better coverage would be recommended for accurate sampling. Hence, "coverage error"
The reduction expressed as a fraction of the original price is
80.00/249.99 ≈ 0.3200128 = 32.00128/100 = 32.00128%
The reduction in price was about 32%.
The maximum number of minutes she could use her phone is 150
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
