All categories

3 years ago

Help me with this please !!

Mathematics

1 answer:

avanturin [10]3 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the line y = - x

a point (x, y ) → (- y, - x ), thus

T(- 1, 3 ) → T'(- 3, 1 )

U(- 1, 10 ) → U'(- 10, 1 )

V(- 2, 4 ) → V'(- 4, 2 )

You might be interested in

14 minus 48 plus 93 divided by -95

ankoles [38]

Answer:

The answer would be -35.

Step-by-step explanation: (14-48) + (93 DIVIDED BY (-95))= -34.9789473684 WHICH ROUNDS OUT TO BE -35.

7 0

3 years ago

Having a hard time with this

raketka [301]

Answer:

the correct answer is D

Step-by-step explanation:

because the -9 5/8 is in absolute value marks.

6 0

3 years ago

Can anyone solve part ii)

tia_tia [17]

Answer:

130 cm

Step-by-step explanation:

hope this helps u

7 0

2 years ago

What is the y-value of the vertex of the function f(x) = –(x + 8)(x – 14)?

maxonik [38]

we have

$f(x)=-(x+8)(x-14)$

Convert to vertex form

$f(x)=-(x+8)(x-14)\\f(x)=-( x^{2}-14x+8x-112) \\f(x)=-( x^{2}-6x-112)\\f(x)=-x^{2}+6x+112$

we know that

the equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

$f(x)=-x^{2}+6x+112$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-112=-(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-112-9=-(x^{2}-6x+9)$

$f(x)-121=-(x^{2}-6x+9)$

Rewrite as perfect squares

$f(x)-121=-(x-3)^{2}$

$f(x)=-(x-3)^{2}+121$

the vertex is the point $(3,121)$

therefore

<u>the answer is </u>

The y-value of the vertex is $121$

8 0

3 years ago

PLEASE HELP!

beks73 [17]

1 ticket =.5
12=.42
25=.40
50=.5
120=.42
I would suggest that they constantly lower the rate per ticket as the number of tickets increases so for example
1t=.5/ticket
12t=.42/ticket
25t=.38/ticket
50t=.35/ticket
120t=.30/ticket

8 0

2 years ago