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timama [110]
3 years ago
11

Worth 20+ points! Answer all parts and will award brainliest! Please show work

Mathematics
1 answer:
eduard3 years ago
4 0
Factor the following:
x^2 - 5 x - 24
Hint: | Factor x^2 - 5 x - 24 by finding two numbers whose product is -24 and whose sum is -5.
The factors of -24 that sum to -5 are 3 and -8. So, x^2 - 5 x - 24 = (x + 3) (x - 8):
Answer:  (x + 3) (x - 8)

___________________________________________________________

Factor the following:
49 x^2 - 64
Hint: | Express 49 x^2 - 64 as a difference of squares.
49 x^2 - 64 = (7 x)^2 - 8^2:
(7 x)^2 - 8^2
Hint: | Factor the difference of two squares.
Factor the difference of two squares. (7 x)^2 - 8^2 = (7 x - 8) (7 x + 8):
Answer:  (7 x - 8) (7 x + 8)
<span>-24 + 15 x + x^2 
</span>
____________________________________________________________

Factor the following:
x^2 - x - 110
Hint: | Factor x^2 - x - 110 by finding two numbers whose product is -110 and whose sum is -1.
The factors of -110 that sum to -1 are 10 and -11. So, x^2 - x - 110 = (x + 10) (x - 11):
Answer: (x + 10) (x - 11)___________________________________________________________

Factor the following:
49 x^2 - 64
Hint: | Express 49 x^2 - 64 as a difference of squares.
49 x^2 - 64 = (7 x)^2 - 8^2:
(7 x)^2 - 8^2
Hint: | Factor the difference of two squares.
Factor the difference of two squares. (7 x)^2 - 8^2 = (7 x - 8) (7 x + 8):
Answer:  (7 x - 8) (7 x + 8)

_______________________________________________________

Factor the following:
25 x^2 + 40 x - 10
Hint: | Factor out the greatest common divisor of the coefficients of 25 x^2 + 40 x - 10.
Factor 5 out of 25 x^2 + 40 x - 10:
Answer: 5 (5 x^2 + 8 x - 2)

__________________________________________________________

Factor the following:
9 x^2 + 3 x^2 - 6 x
Hint: | Add like terms in 9 x^2 + 3 x^2 - 6 x.
3 x^2 + 9 x^2 = 12 x^2:
12 x^2 - 6 x
Hint: | Factor common terms out of 12 x^2 - 6 x.
Factor 6 x out of 12 x^2 - 6 x:
Answer: 6 x (2 x - 1)

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A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 150 li
Anika [276]

Answer:

N(AUC∩B') = 121

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121

Step-by-step explanation:

Let A represent snickers, B represent Twix and C represent Reese's Peanut Butter Cups.

Given;

N(A) = 150

N(B) = 204

N(C) = 206

N(A∩B) = 75

N(A∩C) = 100

N(B∩C) = 98

N(A∩B∩C) = 38

N(Total) = 500

How many students like Reese's Peanut Butter Cups or Snickers, but not Twix;

N(AUC∩B')

This can be derived by first finding;

N(AUC) = N(A) + N(C) - N(A∩C)

N(AUC) = 150+206-100 = 256

Also,

N(A∩B U B∩C) = N(A∩B) + N(B∩C) - N(A∩B∩C) = 75 + 98 - 38 = 135

N(AUC∩B') = N(AUC) - N(A∩B U B∩C) = 256-135 = 121

N(AUC∩B') = 121

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121

See attached venn diagram for clarity.

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is the shaded part

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GuDViN [60]

Answer:

like 6 is the factor in both monomials then you can factor like this

6(y^2-1)

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