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NNADVOKAT [17]
3 years ago
7

What's 420 seconds to 10 minutes

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0
Seventeen (17) minutes!
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(5 marks)
Shtirlitz [24]

I thought this right but sorry if it is wrong

first make the 6% in amount by 6×10,000÷100=3600

then, the convert 4 year into month by (4×12)=48month. after that divide 48months by 4 month.i.e.48÷4=12.at last multiply 12 by 3600.i.e. 12×3600=43200

3 0
2 years ago
How to now your timetables by your hands
Ivenika [448]
1
Hold your hands out in front of you with your palms facing up. Each of your ten fingers represent a number. Moving from your left thumb to your right thumb, count out the numbers from one to ten. 2 Point the finger you want to multiply by nine down towards your body. For example, if you want to solve (9x3) you will want to hold down your middle finger on your left hand. The middle finger represents the number three because, if you count your fingers from one to ten beginning with your left thumb, your middle finger is the third finger. 3 Solve the problem by counting fingers to the left and right. First count the fingers to the left of your bent finger - in this case there should be two. Next count the fingers to the right of your bent finger - in this case there should be seven. The first digit of the answer is 2 and the second digit is 7. The answer is 27![1]
7 0
3 years ago
Read 2 more answers
Find the lengths of "x"
yanalaym [24]
Using pythagorean's theorem
a^2+b^2=c^2

a being 3 
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
4 0
2 years ago
Question 1 (1 point)
taurus [48]

Answer:

question no 1:slope=5

Step-by-step explanation:

let(x=5andy=8)(a=7andb=18)

now

slope=(b-y)/(a-x)=(18-8)/(7-5)=5

5 0
2 years ago
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HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
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