Answer:
24 edges, 24 vertices, 8 faces - For that weird Cylender thing.
Step-by-step explanation:
There are six faces on sides (and two on both tops, these don´t have vertices or edges of their own), 4 edges on each one, 4 vertices on each one.
Answer: $4.50
Step-by-step explanation:
6+6+3.5= 15.5 paid with a 20 so 4 dollars and 50 cents change
If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)? The answer is No. We cannot. See the explanation below.
<h3>What is the justification for the above position?</h3>
Again, 'No,' is the response to this question. The justification for this is that the value of a function does not depend on the function's limit at a given moment.
This is particularly clear when we consider a question with a gap. A rational function with a hole is an excellent example that will help you answer this question.
The limit of a function at a position where there is a hole in the function will exist, but the value of the function will not.
<h3>What is limit in Math?</h3>
A limit is the result that a function (or sequence) approaches when the input (or index) near some value in mathematics.
Limits are used to set continuity, derivatives, and integrals in calculus and mathematical analysis.
Learn more about limits:
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Answer:
Solve for
x
by simplifying both sides of the equation, then isolating the variable.
Exact Form:
x
=
5
/4
Decimal Form:
x
=
1.25
Mixed Number Form:
x
=
1 1/4
Step-by-step explanation:
THE ANSWER IS C
There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
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