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Gelneren [198K]
3 years ago
5

Sarah bought a mango tree that grows 4 cm each day. It was 10 cm tall when she bought it and now it is 82 cm. Write an equation

to express the growth of this tree. Let "x" represent the number of days Sarah has owned the tree.
Mathematics
1 answer:
Serjik [45]3 years ago
3 0
4x+10=82 The 4 is how much it grows each day and the x is the number of days she had it. and the 10 is how tall it was when she got the tree. the 82 is how high it is now.







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What is an equation of the line that passes through the points (4,1) and (8, -3)?
Andreas93 [3]

Answer:

y=-x+5

Step-by-step explanation:

first, let's find the slope of the line (m), using the equation (y2-y1)/(x2-x1)

here are the given points: (4,1) and (8,-3)

label the points:

x1=4

y1=1

x2=8

y2=-3

now substitute into the equation

m=(-3-1)/(8-4)

m=(-4)/4

m=-1

the slope of the line is -1.

Now, use slope-point form, which is y-y1=m(x-x1)

substitute the numbers into the equation

y-1=-1(x-4)

do distributive prop

y-1=-x+4

add 1 to both sides

y=-x+5

the equation of the line is y=-x+5

hope this helps :)

7 0
3 years ago
A farmer has a soybean field with an area of 55 square meters and a cornfield with an area of 58 square meters. he also has a wh
dexar [7]

A farmer has order the fields from least area to greatest area is,

Soybean field < Cornfield  < Wheat field.

Based on the given conditions,

A farmer has a soybean field with an area = 55 square meters

A farmer has a corn field with an area = 58 square meters

He also has a wheat field that is 52 times the size of the soybean field.

So,

We can write,

52 times the size of the soybean field.

That means,

= 55 * 52

Calculate the product or quotient,

= 2860

Wheat field = 2860

Hence,

Soybean field = 55

Cornfield = 58

Wheat field = 2860

Soybean field < Cornfield  < Wheat field

Therefore,

A farmer has order the fields from least area to greatest area is,

Soybean field < Cornfield  < Wheat field.

To learn more about information visit Area problems :

brainly.com/question/16735292

#SPJ4

5 0
1 year ago
Miss Robinson has 750 stickers. Everyday she gives out 100 stickers. How many days till she has 250?
Rina8888 [55]
750 - 250 = 500
500 / 100 = 5

She has 5 days til she has 250 stickers remaining.
3 0
1 year ago
A presidential candidate's aide estimates that, among all college students, the proportion who intend to vote in the upcoming el
inessss [21]

Answer:

z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24  

p_v =P(z  

If we compare  the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

Step-by-step explanation:

Assuming the following question: A presidential candidate's aide estimates that, among all college students, the proportion p who intend to vote in the upcoming election is at least 60% . If 127 out of a random sample of 240 college students expressed an intent to vote, can we reject the aide's estimate at the 0.1 level of significance?

Data given and notation

n=240 represent the random sample taken

X=127 represent the college students expressed an intent to vote

\hat p=\frac{127}{240}=0.529 estimated proportion of college students expressed an intent to vote

p_o=0.6 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that at least 60% of students are intented to vote .:  

Null hypothesis:p \geq 0.6  

Alternative hypothesis:p < 0.6  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare  the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

7 0
3 years ago
Which of the points is on a line with positive slope?
zaharov [31]
(5,0) and (8,4)

it’s the only one when graphed that the line (from left to right) goes up,
6 0
3 years ago
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