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Lelu [443]
3 years ago
15

Circle the perfect squares

Mathematics
1 answer:
ddd [48]3 years ago
8 0
No circle can never be the perfect squares 
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Hurry :(
Naya [18.7K]

Answer:

The answer is d=37 in

Step-by-step explanation:

3 0
3 years ago
Write these fractions in order size smallest first show you're working 5/12 1/3 4/9 11/27
Bezzdna [24]
First find the lowest common multiple of the denominators which are 12 3 9 and 27 these all go into 108. Next divide 108 by the original denominators for example 108/12 is 9 then times 9 by the numerator which is 5 and you get 45 so the first one is 45/108. Do this for them all and order by the size of the numerator
5 0
3 years ago
Is floor(x) periodic?
diamong [38]

If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.

The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.

Conclusion: The function floor(x) is <u>not</u> periodic.

4 0
3 years ago
Read 2 more answers
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
PLEASE HELP IF YOU CAN EXPLAIN IT THAN THATD BE AMAZINGGGGGG I don’t know which to pick I’m stuck
GaryK [48]

Answer:

1st box ... can be the answe

5 0
3 years ago
Read 2 more answers
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